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Find the largest number which divides 2053

WebThe greatest common factor of two or more whole numbers is the largest whole number that divides evenly into each of the numbers. ... Given the list of common factors for each number, the GCF is the largest number …

V. Answer the following questions : 4×4=16 34. Find the solution …

WebApr 1, 2024 · Hint: Firstly subtract the remainders from the number so that actual numbers and can be obtained and then calculate their factors. So the common factors among both … WebMay 20, 2014 · Find the largest number that will divide 2053 and 967 and leaves a remainder of 5 and 7 respectively. - Brainly.in srishtu 21.05.2014 Math Secondary … saturn tonight sky https://h2oattorney.com

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WebFind the largest number which divides 2053 and 967 and leaves a remainder of 5 and 7 respectively. So, 64 is the greatest number which divides 2053 and 967 leaving the … WebMay 8, 2024 · closed May 9, 2024 by RupamBharti Find the largest number which is divided by 2053 and 967, left the remainder as 5 and 7 respectively. real numbers class-10 1 Answer +1 vote answered May 8, … WebQ. Find the largest number that divides 2053 and 967 and leaves a remainder of 5 and 7 respectively. Find the largest number which divides 705 and 1053 leaving a reminder … saturn third largest moon

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Find the largest number which divides 2053

22. Find the largest number that divides 2053 and 967 …

WebFind the largest number that divides 2053 and 967 and leaves . The largest number is 108. What is the largest number that divides 626 3127 and 15628 . Answer: In order to find the largest number which divides 626, 3127 and 15628 leaving remainders 1, 2 and 3. We get. 626 1 = 625. 3127 2 = 3125. WebFind the largest number that divides 2053 and 967 and leaves a remainder of 5 and 7 respectively. Answer. Verified. Hint: H.C.F can be defined as the highest number which divides the given numbers and gives remainder zero. Apply this rule to get an answer.

Find the largest number which divides 2053

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Web1) number 8 because if you divide 248 with 8 you'll get 31. 2) number 3 because if you divided 6,123 ang 3 then you'll get 2,041 . 3) number 5 because if you divided 1,255 and 5 then you'll get 251 (I'm kinda starting to get lazy so … WebMay 12, 2013 · It is given that on dividing 2053 by the required number, there is a remainder of 5. This means that 2053 – 5 = 2048 is exactly divisible by the required …

WebApr 7, 2024 · Now, the first number is given as 2053 which is divided by N and given remainder 5. Now, if we subtract 5 from 2053, we get 2053 – 5 = 2048 which will give remainder zero if we divide it by N now. For second … WebIt is given that on dividing 2053 by the required number, there is a remainder of 5. This means that 2053 – 5 = 2048 is exactly divisible by the required number. Similarly, 967 – …

WebFind the largest number that divides - First we have to determine the greatest common factor of 320 of 740 after subtracting 5 from each number. Then the ... Find the largest number that divides 2053 and 967 and leaves a remainder of 5 This means that 20535=2048 is exactly divisible by the required number. WebJan 27, 2024 · Find the largest number that divides \ (2053\) and \ (967\) and leaves a remainder of \ (5\) and \ (7\) respectively. Ans: It is given that on dividing \ (2053\) by the required number, there is a remainder of \ (5.\) This means that \ (2053 – 5 = 2048\) is exactly divisible by the required number.

WebMar 28, 2024 · CHITRANG MATHS CLASSES Find the largest number that divides 2053 and 967 and leaves a remainder of 5 and 7 respectively. 1,440 views Mar 28, 2024 Class 10- Real Numbers- Find the...

WebMar 28, 2024 · CHITRANG MATHS CLASSES Find the largest number that divides 2053 and 967 and leaves a remainder of 5 and 7 respectively. 1,440 views Mar 28, 2024 Class … should i use diaper cream every timeWebJul 1, 2009 · The largest number is = HCF(2048,960) =64 -9 View Full Answer Rahulsiddharth answered this 2053-5=2048 967-7=960 2048=2x2x2x2x2x2x2x2x2x2x2 … saturn toniesWebMay 12, 2013 · It is given that on dividing 2053 by the required number, there is a remainder of 5. This means that 2053 – 5 = 2048 is exactly divisible by the required number. Similarly, 967 – 7 = 960 is also exactly divisible by the required number. The required number is the largest number satisfying the above property. saturn through the house navamsaWebApr 16, 2024 · = 2×2×2×2×2×2 = 64 Therefore, the largest number that divides 2053 and 967 and leaves a remainder as 5 and 7 respectively is 64. There's an alternate method too: Let m be the required number. Now, on dividing 2053 and 967 by m let the quotients be q1 and q2 respectively, so, by Euclid 's division lemma, 2053 = mq1 + 5 ---- (i) saturn three cool factsWebMar 12, 2024 · 2053 - 5 = 2048 and 967 - 7 = 960 Prime factorisation of 2048 and 960 are as follows, 2048 = 211 and 960 = 26 × 3 × 5 HCF (2048, 960) = 26 =64 Therefore, the … should i use dish soap to wash my pet bowlsWebFind the largest number that divides 2053 and 967 and leaves a remainder of 5 and 7 respectively. A 64 B 35 C 96 D 72 Medium Solution Verified by Toppr Correct option is … saturn tonight\u0027s skyWebFind the largest number that divides 2053 and 967 and leaves a remainder of 5 This means that 20535=2048 is exactly divisible by the required number. Find the greatest number which divides 120, 165 and 210 should i use deodorant