How many 176 resistors are required

WebR_total = (R1 * R2) / (R1 + R2) Where R1 and R2 are the values of the two resistors. To calculate the number of 176 ohm resistors required in parallel to achieve a specific resistance, you need to use the following formula: WebQ 10: How many 176 Ω resistors (in parallel) are required to carry 5 A on a 220 V line? Ans: For x number of resistors of resistance 176 Ω, Here Supply voltage, V = 220 V Current, I = 5 A Equivalent resistance of the combination = R, given as From Ohm’s law, ∴four resistors of 176 Ω are required to draw the given amount of current. Important Links

How many 176 ohm resistors(in parallel) are required to carry 5 a …

WebHow many 176Ω resistors (in parallel) are required to carry 5 A on a 220 V line? Solution For x number of resistors of resistance 176Ω, the equivalent resistance of the resistors … WebHow many 176 Ω resistors (in parallel) are required to carry 5 A on a 220 V line? DARSHAN CLASSES 9,159 views Apr 26, 2024 Q10. How many 176 Ω resistors (in parallel) are … fly from la to bali https://h2oattorney.com

How many 176 Ω resistors (in parallel) are required to carry 5 A on …

WebApr 8, 2024 · Complete step by step answer: We have given here to find the number of \ [176\Omega \] resistors needed to carry \ [5A\] on a \ [220V\] line. Let, the number of resistors needed is \ [x\]. Hence, the equivalent resistance of the \ [x\] number of resistors will be when connected in parallel, WebHow Many 176 ω Resistors (In Parallel) Are Required to Carry 5 a on a 220 V Line? CBSE English Medium Class 10. Question Papers 939. Textbook ... Therefore, four resistors of 176 Ω are required to draw the given amount of current. Concept: System of Resistors - Resistances in Parallel. WebNow, as per Ohm’s Law, we get, V I = 176 x V I = 176 x ⇒ x = 176×5 220 = 4 x = 176 × 5 220 = 4 Hence, in order to draw the required amount of current, four 176 Ω resistors will be … fly from lax to

How many 176 ohms resistors ( in parallel) are required to

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How many 176 resistors are required

How many 176 ohm resistors (in parallel) are required to …

WebMar 14, 2024 · Hence using the Ohm’s law and the value of resistance from equation (1), we get: V = I R n e t ⇒ 220 = 5 ( 176 N) ⇒ N = ( 176 44) ⇒ N = 4. Hence, 4 of the 176 Ω resistors in parallel would be required to get a net current of 5A flowing through a 220V line. WebMar 21, 2024 · Note that you can connect two resistors ( R1 and R2) in two ways: parallel and series. The resulting resistance ( Rp and Rs respectively) in those cases are: Rs = R1 …

How many 176 resistors are required

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WebTo calculate the number of 176 ohm resistors required in parallel to achieve a specific resistance, you need to use the following formula: N = R_desired / R_single Where N is the … WebApr 5, 2024 · Therefore, current through 12 Ω resistor = 0.67 A. 12. How many 176 Ω resistors (in parallel) are required to carry 5 A on a 220 V line? Suppose n resistors of 176 Ω are connected in parallel. 1/R = 1/176 + 1/176 + ……….n times 1/R = n/176 or R= 176/n Ω By Ohm’s law R=V/I 176/n = 220/5 n= (176 x 5)/220 = 4 13.

WebMar 30, 2024 · NCERT Question 10 How many 176 Ω resistors (in parallel) are required to carry 5 A on a 220 V line? Current = I = 5 A Potential difference = V = 220 V Resistance of … Web1 R = x× 1 (176) 1 R = x × 1 ( 176) R = 176 x 176 x. Now, as per Ohm’s Law, we get, V I = 176 x V I = 176 x. ⇒ x = 176×5 220 = 4 x = 176 × 5 220 = 4. Hence, in order to draw the required amount of current, four 176 Ω resistors will be needed. Related Questions:

WebOct 3, 2024 · We know that according to Ohm’s Law, V = IR. Therefore, R = V/I = 220/5 = 44ohm. Now since n such resistors are connected in parallel,so. 1/R = n/176. or, 1/44 = … WebI ( current ) = V (voltage ) / R ( resistance ) . hence to carry 5A at 220 V supply Resistance required V / I = 220 / 5 = 44 OHMS. In parallel circuit 1/R = 1/R1 + 1/ R2 + 1 / R3 so on …. Hence 1 / 44 = n / 176 when n = no of parallel resistance so n = 176 / …

WebClick here👆to get an answer to your question ️ How many 176 Ω ?resistor(in parallel) are required to carry 5 A in 220 V line. Solve Study Textbooks Guides. Join / Login. Question . ... Calculate the equivalent resistance of the two resistors of 100 ... green leaf express canadaWebJun 17, 2016 · Now for x number of resistors of resistance 176 Ω, the equivalent resistance of the resistors connected in parallel is 44 Ω. 1/44 = 1/176 + 1/176 + 1/176 .....χ times. 1/44 = x / 176 => x = 176/ 44 => x = 4. Therefore, 4 resistors of 176 Ω are required to draw the given amount of current. I hope, this will help you___ . Thank you green leaf extended careWebMar 29, 2024 · (a) For highest resistance according to question resistances must be connected in series: 4 Ω, 8 Ω, 12 Ω, 24 Ω R 1 = 4 Ω R 2 = 8 Ω R 3 = 12 Ω R 4 = 24 Ω Total resistance in series = R 1 + R 2 + R 3 + R 4 = 4 + 8 + 12 + 24 = 48 Ω Now, resistance is maximum when connected in series. greenleaf explainedWebFind many great new & used options and get the best deals for Ohmite Two Ganged 35 Ohm 1.0 Amp Wire Wound Potentiometers at the best online prices at eBay! ... Vitreous Enamel Adjustable Wire-Wound Power Resistors, 100 Watts. $5.59 + $4.50 shipping. Ohmite 12 Ohm 2.04 Amp Wire Wound Potentiometer ... Minimum monthly payments are required ... fly from lax to fijiWebAns: For x number of resistors of resistance 176 Ω, Here Supply voltage, V = 220 V Current, I = 5 A Equivalent resistance of the combination = R, given as From Ohm’s law, ∴four … green leaf express reviewsWebMar 24, 2024 · Best answer Let the resistors be x’ Resistance = 176Ω As per ohm’s law . V = IR R = V I V I Here, V = 220 V, I = 5A ∴ Four resistors (in parallel) are required to carry 5A on a 220 V line. ← Prev Question Next Question → Find MCQs & Mock Test JEE Main 2024 Test Series NEET Test Series Class 12 Chapterwise MCQ Test Class 11 Chapterwise Practice … fly from lax to nycWebApr 30, 2024 · 4 Resistors are required. Step-by-step explanation: Given: Volts = 220 Volts. Current = 5 Ampere. Resistance of each resistor, R = 176 Ohms. No of resistors = n. We know that: v = RpI. ∴ ∵ . Taking N to the other side we … green leaf extension cord winder